数组解构赋值

倘若A代表人生的成功，那么公式是：A =X+Y+Z。X是工作，Y是游戏，z是保持缄默。——（美）爱因斯坦

我们以前从一个数组中获取第一项，可能是如下写法：

let list = [1,2,3]
let i = list[0]

有了解构赋值，可以如下写法：

let list = [1,2,3]
let [i] = list

如果稍微复杂点，例如下面这样从对象中取出来数组：

let ruben = {hobby:['anime']}
let favorite = ruben.hobby[0]

就可以写成：

let ruben = {hobby:['anime']}
let {hobby:[favorite]} = ruben

如果再复杂点

let ruben = {hobby:['anime']}
let achao = {favorite:undefined}
achao.favorite = ruben.hobby[0]

可以写成

let ruben = {hobby:['anime']}
let achao = {favorite:undefined}
[achao.favorite] = ruben.hobby

以及

let ruben = {hobby:['anime']};
let achao = {favorite:undefined};
({hobby:[achao.favorite]} = ruben);

关键在于，两边的结构要一致，而且不能使用{}作为代码开头，会被解析为代码块

我们最后来一个收尾

let ruben = {hobby:[{english:'ruben',chinese:'阿超',behavior:()=>'看动漫'}]};
let achao = {weekend:{todo:undefined},names:[]};
achao.weekend.todo = ruben.hobby[0].behavior;
achao.names = [ruben.hobby[0].english,ruben.hobby[0].chinese];

写成：

let ruben = {hobby:[{english:'ruben',chinese:'阿超',behavior:()=>'看动漫'}]};
let achao = {weekend:{todo:undefined},names:[]};
({hobby:[{english:achao.names[0],chinese:achao.names[1],behavior:achao.weekend.todo}]} = ruben);